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Find an equation for the tangent to the curve y=1+
sketch the curve using the parametric equation to plot the points. use an arrow to indicate the direction the curve is traced as
0 answers
asked by
Sammy
664 views
given the equation of the curve as y=8-2x^2
(a) find equations of tangent and the normal to this curve at the point where x=a.
1 answer
asked by
grian
496 views
Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 .
a. Show that dy/dx= (4x-2xy)/(x^2+y^2+1) b. Write an equation of each
3 answers
asked by
Taeyeon
2,335 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
1 answer
asked by
Craig
987 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
3 answers
asked by
stephanie
1,994 views
original curve: 2y^3+6(x^2)y-12x^2+6y=1
dy/dx=(4x-2xy)/(x^2+y^2+1) a) write an equation of each horizontal tangent line to the
0 answers
asked by
Rainie
693 views
Find an equation of the tangent(s) to the curve at a given point. Then graph the curve and the tangent(s).
x = 6sin(t), y = t^2 +
2 answers
asked by
Daniel
1,583 views
Find the equation of the curve through (4,2) whose tangent (for x > 0)
forms an angle with the x-axis, the tangent of which is
1 answer
asked by
Anonymous
458 views
. Given that x²cos y_sin y=0,(0,π).
A. Verify that the given points on the curve. B.use implicit differention to find the slope
1 answer
asked by
Abdullah11
653 views
Linear approximation:
Consider the curve defined by -8x^2 + 5xy + y^3 = -149 a. find dy/dx b. write an equation for the tangent
1 answer
asked by
Katie G
3,548 views