Find ∫cscx(cotx+cscx)dx .

  1. express in sinx1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
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    2. linds asked by linds
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  2. express this in sinx(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
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    2. linds asked by linds
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  3. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
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    2. Lucy asked by Lucy
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  4. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
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    2. Jon asked by Jon
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  5. Prove the identitycscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx
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    2. Anonymous asked by Anonymous
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  6. helloi know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
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    2. CALLIE CALC asked by CALLIE CALC
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  7. Perform the multiplication and use the fundamental identities to simplify.(cotx + cscx)(cotx-cscx) I know that you have to foil
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    2. Hannah asked by Hannah
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  8. Perform the multiplication and use the fundamental identities to simplify.(cotx + cscx)(cotx-cscx) I know that you have to foil
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    2. Hannah asked by Hannah
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  9. hi!ok, i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
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    2. APpreciate student asked by APpreciate student
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  10. Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.(x=theta BTW)
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    2. Jon asked by Jon
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