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Find ∫cscx(cotx+cscx)dx .
express in sinx
1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
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asked by
linds
787 views
express this in sinx
(1/ cscx + cotx )+ (1/cscx- cotx) i got 2sinx is that right?? and B) express in cosx problem: is 1 +
1 answer
asked by
linds
1,414 views
Find a numerical value of one trigonometric function of x if
tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
1 answer
asked by
Lucy
978 views
My previous question:
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
2 answers
asked by
Jon
934 views
Prove the identity
cscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx
3 answers
asked by
Anonymous
1,741 views
hello
i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
asked by
CALLIE CALC
665 views
Perform the multiplication and use the fundamental identities to simplify.
(cotx + cscx)(cotx-cscx) I know that you have to foil
1 answer
asked by
Hannah
708 views
Perform the multiplication and use the fundamental identities to simplify.
(cotx + cscx)(cotx-cscx) I know that you have to foil
0 answers
asked by
Hannah
542 views
hi!
ok, i know that deriv(cscx) = -cscxcotx and that deriv(cos) = -sinx deriv(cotx) = -((cscx)^2) my question is: is this
1 answer
asked by
APpreciate student
501 views
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.
(x=theta BTW)
1 answer
asked by
Jon
650 views