Felicia rewrote a quadratic function in vertex form. h(x)= x^2−6x+7

Felicia rewrote a quadratic function in vertex form.h(x)= x^2−6x+7 Step 1: h(x)= (x^2−6x+ )+7 Step 2: h(x)=(x^2−6x+ 9 )+7
1. 1 answer
2. 39 views
Felicia rewrote a quadratic function in vertex form.h(x)= x^2−6x+7 Step 1: h(x)= (x^2−6x+ 9 )+7 Step 2: h(x)=(x^2−6x+ 9
1. 1 answer
2. 43 views
Felicia rewrote a quadratic function in vertex form.h(x)= x2−6x+7 Step 1: h(x)= (x2−6x+ 9 )+7 Step 2: h(x)=(x2−6x+ 9 )+7
1. 1 answer
2. 32 views
Cole rewrote a quadratic function in vertex form. h(x)=x^2 -6 +7
1. 1 answer
2. 25 views
Cole rewrote the quadratic function h(x) = x^2 - 6x +7 into vertex form, Cole said the vertex is (3.2) is he correct? Show your
1. 3 answers
2. 45 views
Explain the steps necessary to convert a quadratic function in standard form to vertex form.1. Complete the square to rewrite
1. 1 answer
2. 67 views
Cole rewrote a quadratic function in vertex form. h(x)=x^2 -6x+7Cole said that the vertex is (3, 2). Is Cole correct? If not,
1. 1 answer
2. 48 views
April rewrote a quadratic function in vertex form.h(x)=5^2-30x+30 step 1 h(x)=5(x^2-6x+ )+30 step 2 h(x)=5(x^2-6x+9)+30-45 step
1. 2 answers
2. asked by Alex
3. 1,579 views
Quadratic function written in standard form where a, b, and c are constants such that a is not zero.f(x)= ax^2+bx+c Using
1. 1 answer
2. asked by Janet
3. 800 views
Cole rewrote a quadratic function in vertex form.h(x）= x^2 - 6x + 7 Step 1: h (x) = (x^2 - 6x + ) + 7 Step 2: h (x) = (x^2 -
1. 7 answers
2. 50 views