Factor by grouping x3−4x2−4x+16 (1 point) Responses (x+4)(x+2) open paren

  1. Factor by grouping x3−4x2−4x+16 (1 point) Responses (x+4)(x+2) open paren x plus 4 close paren times open paren x plus 2
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  2. Factor by grouping x3−4x2−4x+16𝑥 3 − 4 𝑥 2 − 4 𝑥 + 16 (1 point) Responses (x+4)(x+2) ( 𝑥 + 4 ) ( 𝑥 + 2 )
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    2. cru asked by cru
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  3. Factor Completely. 12p2+20p−8(1 point) Responses 4(3p+1)(p+2) 4 open paren 3 p plus 1 close paren open paren p plus 2 close
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  4. Part A:How can you factor this trinomial and set it up to use the zero product property to solve? x2+11x+30=0 (1 point)
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  5. Part A:How can the following equation be re-written if you factor out the Greatest Common Factor? 12x2−18x=0 (1 point)
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  6. Part A:How can you factor this trinomial so that you can use the zero product property? x2+8x+12=0 (1 point) Responses
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  7. Factor the polynomial Completely. 12x2+12x+3(1 point) Responses 3(2x+1)2 3 times open paren 2 x plus 1 close paren squared
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  8. Given f(x)=(x+5)(2x2−15x+7) , apply the Factor Theorem and determine which of the following is a factor of f(x) .(1 point)
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    2. sayletyler asked by sayletyler
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  9. Question Given that x=2 is a zero of f(x)=x3−3x2−10x+24 , apply the Factor Theorem and factor f(x) into linear factors.(1
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    2. sayletyler asked by sayletyler
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  10. Part A:How can the following equation be re-written if you factor out the Greatest Common Factor? 3x2−15x=0 (1 point)
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