Factor 4cos^2x+4cosx-1=0

Factor4cos^2x+4cosx-1=0
1. 1 answer
2. asked by Katie
3. 877 views
Factor4cos^2x+4cosx-1=0
1. 1 answer
2. asked by Katie
3. 961 views
find all solutions of the equation 4cos^2x-4cosx+1=0
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2. asked by Brielle
3. 1,841 views
f(x)=4sinx/1+cosxfind f'(x) this is what i got and i dunno what i did to get it wrong (4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62
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2. asked by Justin
3. 977 views
Use the Quadratic Formula to solve the equation in the interval [0,2pi). Then use a graphing utility to approximate the angle x.
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2. asked by Poindexter
3. 733 views
What are the steps for solving this?Directions Use the quadratic formula to solve the equation in the interval [0,2PI). Then use
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2. asked by james
3. 1,225 views
Determine the general solution of 8 cos^2x - 4cosx - 1 =0(8cos^2x - 4cosx)/8 =1/8 cos^2x - 4cosx=1/8 cos^2x/cosx =1+4cosx/cosx
1. 1 answer
2. asked by Bontle
3. 744 views
Let f(x)=9sinx/2sinx+4cosx.Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent
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2. asked by Leslie
3. 968 views
Hi, can someone please solve this step-by-step for me? I really don't get it...Directions: Use the quadratic formula to solve
1. 1 answer
2. asked by james
3. 669 views
keep in mind answers should be pi radians or if necessary 3 dec.csc^2-2=0 all angles 4cos^2x-4cosx+1=0 all angles and name 8
1. 2 answers
2. asked by Amanda
3. 753 views