E naught cell for the

  1. E naught cell for the following galvanic cell is +0.254VHg2^2(aq)+2I^-(aq) ==> 2 Hg(l) + I2(s) What is delta G naught for this
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    2. Steve asked by Steve
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  2. Calulate E naught cell for the reaction below5 Cd(s) + 2 MnO4^-(aq) + 16H+(aq)+ 2 Mn2+(aq) + 8 HxsO(l) The oxidation anode must
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    2. Steve asked by Steve
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  3. E naught cell for the following galvanic cell is +0.254V.Hg^2+(aq) + 2I^-(aq) ==> 2 Hg(l) +I2(s) What is the change G naught for
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    2. Steve asked by Steve
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  4. Calculate E naught cell for the reaction b5Cd(s) + 2MnO4-(aq) + 16H+(aq) ==> 5Cd^2+(aq) = 2Mn^2+(aq) + 8H2O(l) given the
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    2. Steve asked by Steve
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  5. Given the following two half-reactions, determine which overall reaction is spontaneous and calculate its standard cell
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  6. Consider the half-reactions:Cu^2+(aq) +2e^- ==> Cu(s) E naught = +0.34V Sn^2+(aq) + 2e^- ==> Sn E naught = -0.14V Fe^2+ + 2e^-
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    2. Steve asked by Steve
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  7. E cell= E naught cell- (0.02570 V/n) lnQwhere Q=1/([H+]^4[SO42-]) calculate E cell at 25 c if [H2SO4]=10.0M help?
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    2. Nia ! Dr.Bob!! please help me!! asked by Nia ! Dr.Bob!! please help me!!
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  8. Determine delta G naught at 298.15K for a 0.50 V voltaic cell if n=3 for that cell.
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    2. Kaitlin asked by Kaitlin
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  9. Given the following standard reduction potentials,Fe^2+(aq) = 2e^- ==> Fe(s) E naught = -0.440V FeS(s) + 2e^- ==> Fe(s) +
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    2. Steve asked by Steve
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  10. Given the following standard reduction potentials,Fe^2+(aq) + 2e^- ==> Fe(s) E naught = -o.440V FeS(s) + 2e^- ==> Fe(s) +
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    2. Steve asked by Steve
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