Did you solve sin2[sin^-1(pi/6)] and

If sin(θ) = -1/√2, find sin2(θ). (Recall that sin2(θ) means (sin(θ))2.)sin2(θ) =
1. 1 answer
2. asked by Jimmy
3. 1,092 views
If A + B + C = 180°, Prove thatSin² (A/2) + sin² (B/2) - sin²(C/2) = 1 – 2cos (A/2) cos (B/2) sin(C/2)
1. 0 answers
2. asked by Kewal
3. 569 views
If A + B + C = 180°, Prove thatSin² (A/2) + sin² (B/2) + sin²(C/2) = 1 – 2sin (A/2) sin (B/2) sin(C/2)
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2. asked by Kewal
3. 476 views
What is the first step. Explain please.Which expression is equivalent to cos^2x + cot^2x + sin2^x? a) 2csc^2x b) tan^2x c)
1. 4 answers
2. asked by Jake
3. 1,239 views
Find the limit as h approaches 0 of sin²(3x+3h) - sin²(3x) / h
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2. asked by Erica
3. 420 views
cos²(θ) – 3sin(θ) – sin²(θ)= –2____________________________ I am having a hard time figuring out what to do. Do I use
1. 2 answers
2. asked by sweetiepie
3. 512 views
solve the equation1. cos(θ) − sin(θ) = 1 2.2 cos(θ) tan(θ) + tan(θ) = 1 + 2 cos(θ) 3. sin(θ) cos(3θ) + cos(θ)
1. 1 answer
2. asked by help!
3. 770 views
Did you solve sin2[sin^-1(pi/6)] and sin[2sin^-1(pi/6)] in the same way?
1. 1 answer
2. asked by anonymous
3. 283 views
Solve the following trigonometry identities.a) 1-cos2(theta) = sin(theta)cos(theta)/cot(theta) b)
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2. asked by Zoë
3. 709 views
Solve the equation algebraically for x wohere 0 </ x< 2 pi.sin2 x = cos x
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2. asked by Anonymous
3. 409 views