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Describe the graph represented by the equation r=4/2+3sin theta .
Identify the polar form of the linear equation 4x+3y=10.
x=rcos(theta),y=rsin(theta) 4x+3y=4rcos(theta)+3rsin(theta)=10
2 answers
asked by
Jon
632 views
Describe the graph represented by the equation r=4/2+3sin theta . (1 point) Responses ellipse, horizontal directrix at a
1 answer
30 views
convert to polar: 2xy=3
A. r=sqrt(3sin theta cos theta) B. r=sqrt[(3sin theta cos theta)/2] C. r=[3/(2sin theta cos theta)]
1 answer
asked by
Sade
546 views
What values for theta(0<_theta<_2pi) satisfy the equation?
3sin theta = sin theta-1
3 answers
asked by
Kirky
504 views
Solve the equation 2sin^2(theta)+3sin(theta)+1=0 for theta.
3 answers
asked by
anonymous
524 views
I'm extremely confused on what to do in part a of this question.
Consider the curve given by x=3sin(theta), y=1+2cos(theta),
1 answer
asked by
Sarah
564 views
Hello! I have this problem:
x(dx)/sqrt(9-x^2) I was wondering why I can't use trig substitution and substitute sqrt(9-x^2) for
1 answer
asked by
Lucy
718 views
finding the equivalent polar equation
2x+3y=6 I got r=6/2cos(theta)-3sin(theta) can anyone check plz
1 answer
asked by
stacey graham
483 views
if 3sin theta =2 and cos greater than 0,with the aid of a diagram determine the value of:
a) tan theta b) sin theta/cos theta c)
1 answer
asked by
LERATO VINJWA
895 views
Perform the indicated operation and simplify
tan^2(theta)-3sin(theta)tan(theta)sec(theta)
1 answer
asked by
Stacey Graham
556 views