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Consider the function y=sqrt(1+cos2x)/2 (everything
Consider the function y=sqrt(1+cos2x)/2
(everything is under the square root) a. Can x take on any real value? b. How large can
1 answer
asked by
Momo
854 views
Solve the equation of the interval (0, 2pi)
cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
4 answers
asked by
Brian
811 views
Choose the option that gives the solution of the initial-value problem
dy dx=(1 + 2 cos2x^2)/y (y > 0), y= 1 when x = 0. Options
0 answers
asked by
albert
582 views
Hello! If you can help me with these 3 questions I would love it!
1. How do you simplify sqrt5 + 6 sqrt 5? I think that it is 5
3 answers
asked by
The Great Undertale fanatic
753 views
I have a question if someone could help, please explain it.
Given b = -1 and h = -1, what is the equation of the graph if the
1 answer
asked by
Megan
526 views
Solve identity,
(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
3 answers
asked by
sh
767 views
find the domain of the real valued function;
f(x) = sqrt(5 - (sqrtx)) my solution: 5 - (sqrt x) >=0 -(sqrt x) >= -5 (sqrt x) <= 5
2 answers
asked by
HARRY
1,362 views
Evaluate sqrt7x (sqrt x-7 sqrt7) Show your work.
sqrt(7)*sqrt(x)-sqrt(7)*7*sqrt(7) sqrt(7*x)-7*sqrt(7*7) sqrt(7x)-7*sqrt(7^2)
1 answer
asked by
Alexa
3,218 views
Which function is shown on the graph below?
10 8 8642 024681012 / 1 point) O y' = sqrt(2x - 6) - 1 O v = sqrt(2x + 6) + 1 O y =
1 answer
asked by
L
95 views
Find the roots of the function f(x)= x^2+2x+2
Determine f(x) a) (x+1-i)(x+1+i) b)(x+1-i sqrt of 2)(x+1+i sqrt of 2)
0 answers
asked by
raven 31791
583 views