Bob has $4000 invested in

  1. you invested $4000 in two accounts paying 2% and 9% annual interest, respectively if the total interest earned for the year was
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    2. ann asked by ann
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  2. Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x𝑓 ( 𝑥 ) = 4000 ( 1.06 ) 𝑥
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    2. ionk asked by ionk
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  3. Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x) = 4000(1.06)^x is the number of years since
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  4. 5.Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x , where x is the number of years
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  5. Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x, where x is the number of years
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  6. Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x, where x is the number of years
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  7. Pizzazz Publications is having some books printed. The printer charges $800 plus $5 per book. What equation could help me find
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  8. How long will it take $4000 to double if it is invested at 7.85%?
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    2. Anonymous asked by Anonymous
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  9. £4000 is invested at 1.5% compound interest.Show that the value of the investment after 2 years is £4120.90. Thanks to anyone
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    2. Alfredo asked by Alfredo
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  10. Keisha invested her savings in two investment funds. The$4000 that she invested in Fund A returned a 10% profit. The amount that
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    2. cristian asked by cristian
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