Articulate the code with respect to reusability. def is_year(year): if

Articulate the following code with respect to reusability.def is_year(year): if year % 4 == 0: print(‘Year is divisible by
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Articulate the code with respect to reusability.def is_year(year): if year % 4 == 0: print(‘Year is divisible by 4’) else:
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Articulate the code with respect to reusability.def is_year(year): if year % 4 == 0: print(‘Year is divisible by 4’) else:
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Writing Computer Programs Quick Check 1 of 51 of 5 Items Question Identify the error in the syntax of the following code: def
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Identify the error in the syntax of the following code:def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else
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Identify the error in the syntax of the following code:def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else
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Identify the error in the syntax of the following code: def is_year(year): if year % 4 == 0: print('Year is divisible by 4')
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Identify the error in the syntax of the following code:def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else
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Identify the error in the syntax of the following code:def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else
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Identify the error in the syntax of the following code:def is_year(year): if year % 4 == 0: print('Year is divisible by 4') else
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