AgNO3+NaOH-->AgOH+NaNO3 give me molecular ,

  1. AgNO3+NaOH-->AgOH+NaNO3give me molecular , total ionic and net ionic???"
    1. answers icon 1 answer
    2. julia asked by julia
    3. views icon 10,515 views
  2. Powdered AgOH is slowly added to 2.0 L of a 0.020 M solution of NaOH until no moreAgOH will dissolve. If Ksp = 1.4 x 10 -8 for
    1. answers icon 3 answers
    2. joseph lungu asked by joseph lungu
    3. views icon 617 views
  3. calculate how many grams of the products listed would be produced by complete reaction of 0.160 mol of the first reactant.
    1. answers icon 0 answers
    2. meagan asked by meagan
    3. views icon 541 views
  4. When solutions of AgNO3 and NaOH react, the balanced molecular equation is as follows:2AgNO3(aq) + 2NaOH(aq) → Ag2O(s) +
    1. answers icon 1 answer
    2. views icon 123 views
  5. When solutions of AgNO3 and NaOH react, the balanced molecular equation is2AgNO3(aq) + 2NaOH(aq) Ag2O(s) + 2NaNO3(aq) + H2O(l)
    1. answers icon 1 answer
    2. michelle asked by michelle
    3. views icon 1,466 views
  6. Which one of the following is a combustion reaction?A. CH4 + 2 O2 CO2 + 2 H2O B. HBr + NaOH NaBr + H2O C. Xe (aq) + H2O(l)
    1. answers icon 1 answer
    2. ashley asked by ashley
    3. views icon 766 views
  7. Product of this reasction?1. Ag(NH3)2Cl + HCl? 2. AgOH + NaOH? 3. PbCl2 + HCl? 4. Pb(OH)2 + NaOH? 5. PbSO4 + (CH3COO)NH4? 6.
    1. answers icon 2 answers
    2. syilfa asked by syilfa
    3. views icon 817 views
  8. Product of this reasction?1. Ag(NH3)2Cl + HCl? 2. AgOH + NaOH? 3. PbCl2 + HCl? 4. Pb(OH)2 + NaOH? 5. PbSO4 + (CH3COO)NH4? 6.
    1. answers icon 0 answers
    2. syilfa asked by syilfa
    3. views icon 629 views
  9. Which of the following is a synthesis reaction?AgNO3 + NaCl → AgCl + NaNO3 PbCO3 → PbO + CO2 SO3 + H2O → H2SO4 Cu + AgNO3
    1. answers icon 1 answer
    2. views icon 64 views
  10. Silver nitrate (AgNO3) reacts with sodiumchloride as indicated by the equation AgNO3 + NaCl → AgCl + NaNO3 . How many grams of
    1. answers icon 1 answer
    2. annonomus asked by annonomus
    3. views icon 1,992 views