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ABCD is a convex cyclic

ABCD is a convex cyclic quadrilateral such that AB=AD and ∠BAD=90∘. E is the foot of the perpendicular from A to BC, and F
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2. asked by harsh
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ABCD is a convex cyclic quadrilateral such that AB=AD and ∠BAD=90∘. E is the foot of the perpendicular from A to BC, and F
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2. asked by harsh
3. 733 views
In the diagram below, each side of convex quadrilateral $ABCD$ is trisected. (For example, $AP = PQ = QB.$) The area of convex
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2. asked by Fiona
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ABCD is cyclic quadrilateral and AB =CD then prove that AC=BD
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2. asked by Hego
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ABCD is a cyclic square. If AB = CD; prove that, AC = BD
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2. asked by dhruba
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) RSTU is a cyclic quadrilateral in a circle of centre O.If RUT is 40°, what are the two values of <ROT (convex and concave)?(b
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2. asked by bliss
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(a) RSTU is a cyclic quadrilateral in a circle of centre O.If RUT is 40°, what are the two values of <ROT (convex and concave)?
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2. asked by bliss
3. 569 views
The sides of convex quadrilateral ABCD are AB = 8, BC = 5, $CD = 5,$ and $DA = 8.$ Diagonals $\overline{AC}$ and $\overline{BD}$
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2. asked by Fiona
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If ABCD is an arbitrary convex quadrilateral, then the area enclosed by ABCD is described bythe formula (1/2) AC*BD*sin(theta) ,
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2. asked by John
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ABCD is a cyclic quadrilateral. BA is produced to E . AD bisects EAC . Prove that DC=DB with reasons
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2. asked by Boitumelo monaisa
3. 165 views