A solution containing excess lead(ii)

  1. If 32.0 mL lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.545 g precipitate, what is
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    2. Hel P. asked by Hel P.
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  2. The class will react 50.00 mL samples of .200 mol/L potassium phosphate with an excess of 0.120 mol/L lead II nitrate solution.w
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    2. Anon asked by Anon
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  3. 50.00 mL samples of 0.200 mol/L potassium phosphate with an excess of 0.120 mol/L lead II nitrate solution.what is the minimum
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    2. Michelle asked by Michelle
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  4. Excess lead (II) nitrate solution is added to 1.30 g of zinc powder and the mixture is stirred. When the reaction is finished
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    2. chem_cg asked by chem_cg
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  5. If 33.8 mL of lead(II) nitrate solution reacts with excess sodium iodide to yield 0.865g of precipitate, what is the molarity of
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    2. Anonymous asked by Anonymous
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  6. A solution containing excess lead(ii) nitrate is reacted with 380.0ML of 0.250mol/L potassium iodide solution. A bright yellow
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    2. Robyn asked by Robyn
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  7. a class reacts 50.00ml samples of 0.200 mol/L potassium phosphate solution with an excess of 0.120 mol/L lead(II) nitrate
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    2. tryme00 asked by tryme00
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  8. What mass of lead (II)chloride would precipitate if a solution containing 8,28 g of lead (II) ions(Pb2+) reacts with excess HCl?
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    2. maria asked by maria
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  9. What mass of lead trioxonitrate (v) that would be required to yield 12gramm of lead chrolde and other addiction of excess sodium
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    2. Samuel asked by Samuel
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  10. We can precipitate out solid lead(II) iodide from an aqueous lead(II) nitrate solution by adding potassium iodide. If we have
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    2. Kierstin asked by Kierstin
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