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A projectile spends 20 seconds

a symmetric projectile spends a total of 20 seconds in the air. it reaches a peak height of 8 meters. how long does it take to
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2. asked by anita
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A symmetric projectile spends a total of 20 seconds in the air. It reaches a peak height of 8 meters. HOw long it takes to reach
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2. asked by Mary
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A projectile is fired upward 200 ft from an observer. The height in feet of the projectile after t seconds is given by s=-16t2 +
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2. asked by Linda
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A projectile spends 20 seconds in the air. It reaches a peak height of 8 meters. How long does it take to reach it's peak
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2. asked by Rosie
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A projectile is shot horizontally at 34.5m/s from the edge of a 55.0metre buildinga) Determine the height of the projectile from
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2. asked by Ara
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A projectile is shot vertically into the air. Its height, h, in metres, after t seconds is approximately modelled by the
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2. asked by Alex
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A projectile is launched from a platform 20 feet high with an initial velocity of 72 feet per second,The height h of the
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2. asked by Brian
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Height of a Projectile.The height of a projectile is described by the equation: s(t)=144t-16t^(2) Where t is in seconds and s(t)
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2. asked by Ashley
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A projectile is launched from a platform 20 feet high with an initial velocity of 48 feet per second, The height h of the
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2. asked by Brooke
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If the vertical component of velocity for a projectile is 7.3 meters/second, find its hang time.A. 1.9 seconds B. 2.5 seconds C.
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2. asked by Lauren01
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