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A 0.5537-g sample containing oxalic

A 0.5537-g sample containing oxalic acid required 21.62 mL of 0.09377 M NaOH for titration. If the reaction is H2C2O4 + 2NaOH
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2. asked by Polly
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The amount of oxalic acid in a sample was determined by the reaction:2Fe3+ + H2C2O4 + 2H2O----> 2Fe2+ + 2CO2 + 2H3O+. In an
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2. asked by Jimmy
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1. A sample of oxalic acid (H2C2O4, with two acidic protons), of volume 46.56 mL was titrated to the stoichiometric point with
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2. asked by Angelica
3. 727 views
two solutions A and B are provided to you. A is a solution of M/50 potassium permanganate. B is a solution of hydrated sample of
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2. asked by neha
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A sample of oxalic acid (H2C2O4, with two acidic protons), of volume 37.09 mL was titrated to the stoichiometric point with
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2. asked by Andrea
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What is the mole of oxalic acid?Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. *
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2. asked by Ivy
3. 1,547 views
What is the mole of oxalic acid?Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. *
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2. asked by Ivy
3. 1,281 views
The LD50 for oxalic acid in rats is 375 milligrams oxalic acid/kilogram of body weight. Assume that the LD50 for oxalic acid in
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2. asked by anonymous
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25.00 mL of a solution of oxalic acid are titrated with 0.2586 m NaOH (aq). The stoichiometric eend point is reached when 43.42
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2. asked by ANONYMOUS
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A sample of g 0.2050 oxalic acid (4.2 H2C2O H2O) required 25.52 mL of KOH solution to complete the neutralization according to
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2. asked by Michaela
3. 673 views