A 0.1028 g impure sample

  1. A 0.1028 g impure sample consists of Na2CO3 was analyzed by the Volhard method. After adding 50.00 mL of 0.06208 M AgNO3, the
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    2. yun asked by yun
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  2. A sodium hydroxide sample is contaminated with sodium chloride. A 0.240 gram sample of this impure sample is dissolved in water
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    2. Sam asked by Sam
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  3. Impure sample of table salt that weighed 0.8421g, when dissolved in water and treated with excess AgNO3, formed 2.044g of AgCl.
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    2. London asked by London
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  4. CrCl3(s) + AgNO3 (aq)= AgCl(s) + Cr(NO3)3(aq)A 0.750 g sample of impure CrCl3 was removed from a bottle that contained 1.75 g of
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    2. jade asked by jade
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  5. A sample of impure magnesium was analyzed by allowing it to react with excess HCl solution:Mg(s) + 2 HCl(aq) → MgCl2(aq) +
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    2. James asked by James
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  6. A sample of impure magnesium was allowed to react with excess HCL solution. After 5.5 gram of the impure metal was treated with
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    2. Anonymous asked by Anonymous
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  7. A 0.670 g sample of impure Al2(SO4)3 reacts with excess BaCl2. If the sample produces 0.760 g of BaSO4, what is the mass percent
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    2. Tevin asked by Tevin
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  8. The mass of potassium iodate (KIO3) contained in an impure sample was determined by titration with sodium thiosulfate (0.1005
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    2. Ami asked by Ami
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  9. The mass of potassium iodate (KIO3) contained in an impure sample was determined by titration with sodium thiosulfate (0.1005
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    2. Gemma asked by Gemma
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  10. A .500 g sample of impure CaO (a solid) is added to 50.0 mL of 0.100 M HCl. The excess HCl is titrated by 5.00 mL of .125 M
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    2. b asked by b
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