8sin^2(x)+6sin(x)-9=0 simplify

8sin^2(x)+6sin(x)-9=0 simplify
1. 1 answer
2. asked by frances
3. 1,270 views
6sin(2x)+3=0How do you find the smallest value of x in the interval 0≤x≤π for which y=0? My work so far: 6sin(2x)=-3
1. 1 answer
2. asked by Autumn
3. 1,108 views
Prove the identity:4x=1-8sin^2x+8sin^4x
1. 1 answer
2. asked by PRELUDE
3. 901 views
How do I take the derivative of 3(sin(x))^2 cos(x)? Are these right--> 3(sin(x))^2 *-sin(x) + cos(x)*6sin(x)*cos(x)=(-3sin(x))^3
1. 1 answer
2. asked by Anonymous
3. 461 views
If we are given 8sin((pi/6)(x+2))+16=20the answers are -1 and 3 because 1/2 can be pi/6 or 5pi/6. However, if y = 10
1. 0 answers
2. asked by Ashley
3. 443 views
Please take a look at DEVON's trig equation at 9:14I must be missing something obvious. If the second had been 3sin 2x it would
1. 0 answers
2. asked by Reiny
3. 707 views
a) Express f(theta) = 4cos theta - 6sin theta in the form r cos(theta + alpha)b) Hence find the general solution of the equation
1. 3 answers
2. asked by Becky
3. 1,333 views
8sin^4(x)
1. 0 answers
2. asked by Anonymous
3. 386 views
6sin(pi/6x)=5
1. 2 answers
2. 100 views
8sin^2x+sinxcosx+cos^2x=4
1. 2 answers
2. asked by LiNnda
3. 4,280 views