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6sin^2(x) - 5sin(x) + 1
6sin^2(x) - 5sin(x) + 1 = 0
solve
6 answers
asked by
Anonymous
1,939 views
6sin(2x)+3=0
How do you find the smallest value of x in the interval 0≤x≤π for which y=0? My work so far: 6sin(2x)=-3
1 answer
asked by
Autumn
1,108 views
the question asks to integrate cos(t)/ (5sin(t)+8)^2 the answer i got was xcos(t)/(5sin(t)+8)^2 this is not right i believe
1 answer
asked by
sonia
507 views
How do I take the derivative of 3(sin(x))^2 cos(x)? Are these right--> 3(sin(x))^2 *-sin(x) + cos(x)*6sin(x)*cos(x)=(-3sin(x))^3
1 answer
asked by
Anonymous
461 views
cos(t)/(5sin(t)+8)^2
the answer i got was: xcos(t)/(5sin(t)+8)^2 this is not right when i put it in what did i do wrong?
5 answers
asked by
sonia
555 views
antiderivative
f''=3x+5sin(x) f(0)=4 f'(0)=4 Find f(x) I got (1/2)x^3-5sin(x)+(15/2)x+(7/2), but it was wrong
0 answers
asked by
Anonymous
528 views
the question asks to integrate cos(t)/(5sin(t)+8)^2 the answer i got was
xcos(t)/(5sin(t)+8)^2 i think the x is wrong but i am
0 answers
asked by
sonia
588 views
Find the length of the entire perimeter of the region inside r=5sin(theta) but outside r=1.
1=5sin(theta) theta=arcsin(1/5)
1 answer
asked by
Joe
1,227 views
40. Express
4 cos 𝑥 + 3 sin 𝑥 in the form Rsin(𝑥 + 𝜃) A. 5Sin(x+36.9) B. 5Sin(x+53.1) C. 7Sin(x+36.9) D. 7Sin(x+53.1)
1 answer
asked by
Benny
159 views
a) Express f(theta) = 4cos theta - 6sin theta in the form r cos(theta + alpha)
b) Hence find the general solution of the equation
3 answers
asked by
Becky
1,332 views