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6cos^2(x)-5cos(x)-6
I got this far, but now I'm stuck...please help
6cos^2theta - 5cos(theta) + 1 = 0 6cos^2theta - 5cos(theta) = -1 cos(theta) *
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asked by
Tara
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6cos^2(x)-5cos(x)-6
1 answer
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Ashleigh
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6cos^2 theta + 5cos theta=1
Solve for theta
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Rivan
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Hi! The question I need help with is 6cos^2x-3 and the directions say to use a double-angle formula to write the expression.
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Which functions of x and y in terms of time t can be derived from this rectangular equation? (x^2/4)+y^2=1
A. x = 2sin t, y =
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Find the volume bounded by r=2-2cos theta and r=-6cos theta
Would this be right 1/2 ∫ [5π/3,π/3] ((-6cos theta)^2 - (2-2cos
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Find the length of the entire perimeter of the region inside r=5sin(theta) but outside r=1.
1=5sin(theta) theta=arcsin(1/5)
1 answer
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(cos^2+6cos x + 9) / (cos x + 3)
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