6.10g of boron reacted completely

  1. 6.10g of boron reacted completely with 22.9g of chlorine to give 29.0g of the metallic chloride. Calculate the empirical formula
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    2. Kenry asked by Kenry
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  2. Boron has only two naturally occurring isotopes. The mass of boron-10 is 10.01294 amu and the mass of boron-11 is 11.00931 amu.U
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    2. Brittany asked by Brittany
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  3. Naturally occuring boron is 80.20% boron-11 and 19.80% of some other isotopic form of boron. What must be the atomic mass of
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    2. Ben asked by Ben
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  4. naturally occurring boron is 80.20% boron 11 (atomic mass= 11.01amu) and 19.80% of some other isoptopic form of boron. what must
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    2. Tom asked by Tom
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  5. When 0.500 moles of boron trichloride react with 1.20 moles hydrogen gas to produce elemental boron and hydrogen chloride gas,
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    2. Matt asked by Matt
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  6. If boron hydride, B4H10, is treated with pure oxygen, it burns to give B2O3 and H2O.2 B4H10(s) + 11 O2(g)  4 B2O3(s) + 10
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    2. Jazmin asked by Jazmin
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  7. Boron is used to dope 1 kg of germanium (Ge). How much boron (B) is required to establish a charge carrier density of
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    2. Ray asked by Ray
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  8. The boron fibers are produced by chemical vapor deposition of boron onto fine tungsten wires of dW=10μm. The final wire
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    2. qwerty asked by qwerty
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  9. Boron exits in two isotopes, boron -10 and boron -11. based on the atomic mass, which isotopes should be more abundant
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    2. Anonymous ;) asked by Anonymous ;)
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  10. Naturally occurring boron is 80.20% boron-11 (of atomic mass 11.01 amu) and 19.80% of some other isotope form of boron. What
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    2. Peter asked by Peter
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