6.0g of impure and hydrous

  1. 6.0g of impure and hydrous Na2SO4 were made up to 1dm^3 of solution neutralize 22.20cm^3 of 0.1mol/dm^3 of HCL.calculate:a)conce
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    2. faith asked by faith
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  2. 6.0g of impure and hydrous Na2SO4 were made up to 1dm^3 of solution neutralize 22.20cm^3 of 0.1mol/dm^3 of HCL.calculate:a)conce
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    2. faith asked by faith
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  3. A sample of impure magnesium was analyzed by allowing it to react with excess HCl solution:Mg(s) + 2 HCl(aq) → MgCl2(aq) +
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  4. Aiieeee!Todays lab...good grief. I was supposed to dissolve 0.3g of impure sulfanilamide in enough ethyl alchohol (95%) and me
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    2. ~christina~ asked by ~christina~
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  5. A sample of impure magnesium was allowed to react with excess HCL solution. After 5.5 gram of the impure metal was treated with
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    2. Anonymous asked by Anonymous
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  6. calculate the mass of impure KOH needed to make up 1.20 L of 0.60 mol/L KOH(aq)? Assume the impure KOH is 84% KOH by mass and
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    2. LG asked by LG
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  7. 25cm3 of 0.1 mole H2SO4 neutralizes 20.0cm3 of impure NaOH containing 3.0g of impure NaOH in 250cm3 Of a solution . calculate
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    2. Basil salvation asked by Basil salvation
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  8. A is a solution of hydrochloric acid containing 3.650g of HCl in 1dm3 of solution. B is asolution of impure sodium carbonate.
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    2. Victor asked by Victor
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  9. D is a solution containing 0.05mol/dm3 of H2SO4E is a solution containing 7.50g/dm3 of impure KOH Solution D was titrated
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    2. Aminah asked by Aminah
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  10. The mass of potassium iodate (KIO3) contained in an impure sample was determined by titration with sodium thiosulfate (0.1005
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    2. Gemma asked by Gemma
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