6-mile perimeter. The length is

  1. You have two formulas to use:A = lw -->area = length times width P = 2l + 2w -->perimeter You know the perimeter, which is 200m
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    2. MathGuru asked by MathGuru
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  2. There is a quadrilateral with a perimeter of 20 cm. Three sided length are 1/5 of the perimeter, 3/10 of the perimeter, and 3/15
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  3. 6-mile perimeter. The length is 4 times the width.what is the length width
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    2. heather asked by heather
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  4. Consider the right triangle shown. Which statement explains the Pythagorean Theorem?A. The sum of the length of leg a and the
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  5. In order to swim one mile in a rectangular pool, I must swim the length of the pool 80 times or swim all the way around the
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    2. Tyler asked by Tyler
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  6. A school has a hurdle track that is 1/5 of a mile long. They are considering extending the track to be 1/4 of a mile long.The
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    2. annite asked by annite
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  7. A school has a hurdle track that is 1/5 of a mile long. They are considering extending the track to be 1/4 of a mile long. The
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    2. drakeboing asked by drakeboing
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  8. A school has a hurdle track that is 1/5 of a mile long. They are considering extending the track to be 1/4 of a mile long. The
    1. answers icon 1 answer
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  9. give the demensions of rectangles with the perimeters of 70 feet and length-to-width ratios of 3 to 4, 4 to 5, and 1 to 1.Ok,
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    2. christine asked by christine
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  10. given the perimeter of a rectangle and either the length or width, find the unknown measurement using the formula.the perimeter
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    2. jackjohnsonb asked by jackjohnsonb
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