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6) rewrite (x+3)^2+y^2=9 in polar form. A: r^2= 3rsin theta
6) rewrite (x+3)^2+y^2=9 in polar form.
A: r^2= 3rsin theta B: r^2= 9rcos theta C: r= -6 cos theta D: r= 3rsin theta 7)Which of
3 answers
asked by
precal
141 views
Identify the polar form of the linear equation 4x+3y=10.
x=rcos(theta),y=rsin(theta) 4x+3y=4rcos(theta)+3rsin(theta)=10
2 answers
asked by
Jon
632 views
rewrite in polar form x^2+y^2-6y-8=0
r^2=6r+6sin theta +8 r^2=6rsin theta +8 r^2=6r+6cos theta +8 r^2=6r cos theta +8
1 answer
asked by
John
719 views
Which is the polar form of the parametric equations x=5cos(theta) and y=5sin(theta) ?
a. r= 5(theta) b. r= 5 c. r= 25 cos (theta)
2 answers
asked by
Vsuf
3,178 views
change equations to polar form:
1) y= -1 2) x^2 + y^2 = 4 how would i do these questions? thank u to convert to polar, you use
0 answers
asked by
hmmmm
601 views
Rewrite in polar form: x^2 + y^2 - 6y - 8 = 0 A) r^2 = 6r + 6 \sin \theta + 8 B) r^2 = 6r \sin...
1 answer
17 views
\sqrt{i} in polar form can be written as r(\cos \theta + i \sin \theta), where r is a real number and 0 \leq \theta \leq
1 answer
asked by
John
705 views
translate this polar equation into a rectangular form:
rsin(2theta)=sin(theta) My answer: r2sin(theta)cos(theta)=sin(theta)
2 answers
asked by
Sara
874 views
Which is the parametric form of the polar equation r=-3theta
A.x=3thats cos theta Y=3theta sin theta B.x=-3theta cos theta
1 answer
49 views
write the following parametric equations as a polar equation
x=t^2 y=2t *r=4cot(theta)csc(theta) *r=2cot(theta)csc(theta)
1 answer
asked by
heheeeee
46 views