502g sample of dry cac03

502g sample of dry cac03 and cacl2 mixture was dissolved in 25ml of 0.925 M HCL solution. What was cacl2 percentage in original
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2. asked by Fai
3. 605 views
1.64g of a mixture of cac03 and mhco3 was dissolved in 50ml of 0.8M hcl. The excess of acid required 16ml of 0.25M naoh for
1. 1 answer
2. asked by Fai
3. 626 views
1.64g of a mixture of cac03 and mgc03 was dissolved in 50ml of 0.8 m Hcl. The excess of acid required 16ml of 0.25< NAOH for
1. 2 answers
2. asked by Fai
3. 1,560 views
1.64g of a mixture of cac03 and mgc03 was dissolved in 50ml of 0.8M hcl. The excess of acid required 16ml of 0.25M naoh for
1. 0 answers
2. asked by Fai
3. 502 views
1.64g of a mixture of cac03 and mgc03 was dissolved in 50ml of 0.8M hcl. The excess of acid required 16ml of 0.25M naoh for
1. 1 answer
2. asked by Fai
3. 473 views
80ml of hcl is added to 2.5gm of pure cac03 when the reaction is over, then 0.5gm cac03 is left. Find the normality of the acidT
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2. asked by Fai
3. 993 views
10L of hard water required 5.6g of line for removing hardness. Hence temporary hardness in ppm of cac03.The answer 1000 ppm=
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2. asked by ken
3. 924 views
1.64g of a mixture of cac03 and mgc03 was dissolved in 50ml of 0.8M hcl. The excess of acid required 16ml of 0.25M naoh for
1. 0 answers
2. asked by Fai
3. 403 views
one litre of a sample hard water contain 4.44mg cacl2 and 1.9mg of mgcl2. What is the total hardness in terms ppm of cac03?
1. 1 answer
2. asked by ken
3. 1,063 views
10L of hard water required 5.6g of lime for removing hardness. Hence temporary hardness in ppm of cac03.The answer 1000 I think
1. 1 answer
2. asked by ken
3. 1,917 views