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5. Suppose $4000 is invested

Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x𝑓 ( 𝑥 ) = 4000 ( 1.06 ) 𝑥
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2. asked by ionk
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Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x) = 4000(1.06)^x is the number of years since
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5.Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x , where x is the number of years
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Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x, where x is the number of years
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Suppose $4000 is invested at 6% interest compounded annually. Our formula is f(x)=4000(1.06)x, where x is the number of years
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you invested $4000 in two accounts paying 2% and 9% annual interest, respectively if the total interest earned for the year was
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2. asked by ann
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Suppose that $4000 is invested at an interest rate of 5.5% per year, compounded continuously. What is the balance after 8 years?
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2. asked by selina
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I'm pretty confused about these problems. We're learning growth and decay, but there are quite a few formulas.1. Suppose $500 is
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Pizzazz Publications is having some books printed. The printer charges $800 plus $5 per book. What equation could help me find
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Suppose 10,000 is invested at 6 percent.how much additional money must be invested at 8 percent to produce a yield on the entire
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2. asked by HELP NEED HELPs!!!!
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