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4cosx + 3 = 0
Determine the general solution of 8 cos^2x - 4cosx - 1 =0
(8cos^2x - 4cosx)/8 =1/8 cos^2x - 4cosx=1/8 cos^2x/cosx =1+4cosx/cosx
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Bontle
766 views
Let f(x)=9sinx/2sinx+4cosx.
Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent
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Leslie
994 views
Complete the table of values that can be used to graph f(x)=−4cosx .(2 points) x f(x)=−4cosx 0 π2 π 3π2 2π
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Complete the table of values that can be used to graph f(x)=−4cosx
.(2 points) x f(x)=−4cosx 0 π2 π 3π2 2π
1 answer
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a. Draw the graphs of y=4cosx and y=2x-x on the same set of axes for -2π<=x<=2π
(done) b. Explain why all these solutions of
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asked by
anon
509 views
Write the equation of the periodic function based on the graph.
(1 point) Responses y=−4cosx y equals negative 4 cosine x
1 answer
125 views
Write the equation of the periodic function based on the graph. (1 point) Responses y=4cosx y equals 4 cosine x y=−4cosx y
1 answer
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The slope of the line normal to the graph of 4 sin x + 9 cos y = 9 at the point (pi, 0) is:
Derivative: 4cosx - 9siny(dy/dx) = 0
15 answers
asked by
Mishaka
4,071 views
4cosx + 3 = 0
1 answer
asked by
Kevin
422 views
If f(x)=3cos^2x-4cosx
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asked by
Kamlendra Singh
411 views