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4cos^2 x - cosx-3 =0
If f(x)=4sinx/1+cosx
then f'(x)=_____? I think that the derivative of 4sinx would be 4cos and cosx would be sinx but I don't know
2 answers
asked by
gnozahs
1,429 views
how do you verify cos3x=4cos^3x-cosx???
0 answers
asked by
lindsey edler
731 views
1. 4sin^2x=3tan^2x-1
2. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2
2 answers
asked by
Michael
3,653 views
4cos^2 x - cosx-3 =0
0 to 2pi SORRY TYPED THE QUESTION WRONG PLESSE HELP
1 answer
asked by
liz
473 views
f(x)=4sinx/1+cosx
find f'(x) this is what i got and i dunno what i did to get it wrong (4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62
1 answer
asked by
Justin
947 views
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,069 views
I'm trying to find all the points on the graph y=4/3cos^3x-cosx where the tangent line is horizontal. I took the derivative,
1 answer
asked by
Jamie
505 views
hey, i would really appreciate some help solving for x when:
sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
0 answers
asked by
elle
712 views
I have a question relating to limits that I solved
lim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
1 answer
asked by
Alex
690 views
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
0 answers
asked by
Dave
1,446 views