4cos^2 x - cosx-3 =0

  1. If f(x)=4sinx/1+cosxthen f'(x)=_____? I think that the derivative of 4sinx would be 4cos and cosx would be sinx but I don't know
    1. answers icon 2 answers
    2. gnozahs asked by gnozahs
    3. views icon 1,429 views
  2. how do you verify cos3x=4cos^3x-cosx???
    1. answers icon 0 answers
    2. lindsey edler asked by lindsey edler
    3. views icon 731 views
  3. 1. 4sin^2x=3tan^2x-12. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2
    1. answers icon 2 answers
    2. Michael asked by Michael
    3. views icon 3,653 views
  4. 4cos^2 x - cosx-3 =00 to 2pi SORRY TYPED THE QUESTION WRONG PLESSE HELP
    1. answers icon 1 answer
    2. liz asked by liz
    3. views icon 473 views
  5. f(x)=4sinx/1+cosxfind f'(x) this is what i got and i dunno what i did to get it wrong (4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62
    1. answers icon 1 answer
    2. Justin asked by Justin
    3. views icon 947 views
  6. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 1,069 views
  7. I'm trying to find all the points on the graph y=4/3cos^3x-cosx where the tangent line is horizontal. I took the derivative,
    1. answers icon 1 answer
    2. Jamie asked by Jamie
    3. views icon 505 views
  8. hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
    1. answers icon 0 answers
    2. elle asked by elle
    3. views icon 712 views
  9. I have a question relating to limits that I solvedlim(x-->0) (1-cosx)/2x^2 I multiplied the numerator and denominator by
    1. answers icon 1 answer
    2. Alex asked by Alex
    3. views icon 690 views
  10. Trigonometric IdentitiesProve: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
    1. answers icon 0 answers
    2. Dave asked by Dave
    3. views icon 1,446 views