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4FeCr2O4+ 8K2CO3+7O2= 2Fe2O3+8K2CrO4+8CO2 how many

4FeCr2O4+ 8K2CO3+7O2= 2Fe2O3+8K2CrO4+8CO2how many grams of FeCr2O3 are required to produce 44g of CO2?
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2. asked by henry
3. 1,695 views
Hello, how would I solve this question? I tried solving it, but I got 109% as my answer which seems incorrect. This is the
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2. asked by Anonymous
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4FeCr2O7 + 8K2C03 + O2 --> 2Fe2O3 + 8K2CrO4 + 8CO2a). How many grams of FeCr2O7 are required to produce 44.0 g of CO2
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2. asked by Nikki
3. 2,313 views
A chemical equation is shown below.4Fe + 3O2 ⟶2Fe2O3 The mass of 2Fe2O3 produced must be equal to A chemical equation is shown
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2. 126 views
Balance this equation!C2H3Br + O2 → 8CO2 + H2O + 2Br2
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2. 64 views
2C4H10(g)+ 1302(g)+8CO2(g)+10H20(g)X Element Number of atoms C H O
1. 1 answer
2. 45 views
Please check if I've balance the equation correctly.C8H18 + 25/2O2 --> 8CO2 + 9H2O
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2. asked by Sarah
3. 593 views
How many grams of H2O (Mm = 18.0 g/mol) are produced in the combustion of 70.0 g of C4H10 (Mm = 58.1 g/mol)?2C4H10 + 13O2 8CO2 +
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2. asked by Anonymous
3. 1,108 views
2c4h10+13o2 8co2+10h2o how many moles of co2 is produced when 76.9g o2 is consumed when butane is burned
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2. asked by AP
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Given the equation below, how many moles of butane (C4H10) must be burned in an excess of O2 to produce 150 g CO2?2C4H10(g) +
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2. asked by Joe
3. 1,719 views