Ask a New Question
Search
4.if cotθ� = -√15/7 ,
For the acute angle θ, given that sinθ=1/7, find the exact value of cotθ.
cotθ=1/√48 cotθ=1/√50 cotθ=√50 cotθ=√48
1 answer
asked by
Stephanie
403 views
Find the exact value of cotθ given secθ=3 and tanθ<0.
cotθ=8√/3 cotθ=−(3/√8) cotθ=1/√8 cotθ=−(√8/3)
3 answers
asked by
Stephanie
332 views
given cotθ = (1/2) √7, find sinθ and cosθ in quadrant I
cotθ = x/y would 1/2 be the x and √7 be the y?
0 answers
asked by
coco
435 views
Simplify the expression (tanθ+cotθ)^2 - (tanθ-cotθ)^2 using algebra and trigonometric identities.
1 answer
asked by
Bob
837 views
Prove the following identities:
a) (cosec θ + cotθ)(cosecθ - cotθ) = cotθtanθ b) 2/(1 + sinθ) + 1/(1- sinθ) = (3sec^2)θ
2 answers
asked by
Proving Identities Question (Trig.)
720 views
Can someone tell me how to do this problem?
(sin^2 θ - cotθ * tan θ)/ cotθ * sin θ Please and thank you.
2 answers
asked by
Ana
439 views
1) given cotθ = 1/2√7, find sinθ and cosθ in quadrant I
2) given tanθ = √5, find secθ and cotθ in quadrant III
4 answers
asked by
coco
801 views
#1 cscθ-cotθ
#2 cosθ(tanθ-secθ) #3 tanθ+sinθ/cscθ+cotθ
3 answers
asked by
lucy
845 views
cosecθ⋅cotθ=2√3
3 answers
asked by
Md fuadul islam
450 views
If sinθ = cotθ, then the value of (cos^2θ + 2cos^3θ + cos^4θ -3) is: (A) 0 (B) -1 (C) -2 (D) -3
1 answer
asked by
Anonymous
302 views