4 AlBr3 + 3 O2

1. 2Na + Cl2 → 2 NaCl2. 2 HgO → 2 Hg + O2 3. Zn + 2 HCl → ZnCl2 + H2 4. PbBr2 + Al2O3 → PbO + AlBr3 4. PbBr2 + Al2O3 →
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A 11 mL sample of a solution of AlBr3 was diluted with water to 23 mL. A 15 mL sample of the dilute solution was found to
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. A 13 mL sample of a solution of AlBr3 was diluted with water to 56 mL. A 25 mL sample of the dilute solution was found to
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Aluminum reacts spontaneously with bromine to produce AlBr3.If 218.08 grams of aluminum reacts with 258.21 grams of bromine and
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Column A1. 2 H2O → 2 H2 + O2 : 2 H2O → 2 H2 + O2 2. 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O : 2 C2H6 + 7 O2 → 4 CO2 + 6 H2O 3. 2
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4 AlBr3 + 3 O2 → 2 Al2O3 + 6 Br2
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what is the net ionic equation forAlBr3(aq) + 3LiOH(aq)
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Balance the following equation:PbBr2 + Al2O3 → PbO + AlBr3
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2H20 -> 2H2 + 022C2H6 + 702 -> 4 CO2 + 6H20 2 Na + Cl2 -> 2 NaCl 4 AlBr3 + 302 -> 2 A1203 + 6 Br2 KCI + Nal -> KI + NaCI
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Calculate the percentage of water in Aluminum bromide hexahydrate, AlBr3 •6H2O.
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