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3 I- (aq) +H3AsO4 (aq)
H3AsO4 reacts with water as follows:
H3aso4+h20<=>h2aso4- + h30+ The conjugate base of h3aso4 in this reaction is
1 answer
asked by
Anonymous
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The oxidation of iodide ion by arsenic acid, H3AsO4, is described by the balanced equation
3I−(aq)+H3AsO4(aq)+2H+(aq)→
1 answer
asked by
Joe
1,521 views
The oxidation of iodide ion by arsenic acid, H3AsO4, is described by the balanced equation
3I−(aq)+H3AsO4(aq)+2H+(aq)→
2 answers
asked by
Joe
2,281 views
The oxidation of iodide ions by arsenic acid in acidic aqueous solution occurs according to the net reaction H3AsO4 + 3I – + 2
1 answer
asked by
Jenna
3,751 views
Arsenic acid (H3AsO4) is a triprotic acid with Ka1 = 5 10-3, Ka2 = 8 10-8, and Ka3 = 6 10-10. Calculate [H+], [OH -], [H3AsO4],
15 answers
asked by
Cab
9,815 views
"Arsenic acid (H3AsO4) is a triprotic acid with Ka1 = 5 10-3, Ka2 = 8 10-8, and Ka3 = 6 10-10. Calculate [H+], [OH ‾ ],
2 answers
asked by
Clur
1,422 views
Arsenic acid (H3AsO4) is a triprotic acid with Ka1 = 5 10-3, Ka2 = 8 10-8, and Ka3 = 6 10-10. Calculate [H + ], [OH − ],
1 answer
78 views
Arsenic acid (H3AsO4) is a triprotic acid with Ka1 = 5 ✕ 10-3, Ka2 = 8 ✕ 10-8, and Ka3 = 6 ✕ 10-10. Calculate [H+], [OH
0 answers
asked by
Damian Clarke
892 views
To obtain the rate of the reaction
3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3
0 answers
asked by
Lauren
995 views
To obtain the rate of the reaction
3I-(aq) + H3AsO4(aq) + 2H+(aq) --> I3-(aq) + H3AsO3(aq) + H2O (l) I got that the rate is 1/3
0 answers
asked by
Lauren
501 views