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2tan^-1(tanx/2×tan(π/4-y/2))=tan^-1(sinx×siny/cosx+cosy)
2tan^-1(tanx/2×tan(π/4-y/2))=tan^-1(sinx×siny/cosx+cosy)
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asked by
Mansi
548 views
How do I get (sinx cosy + cosx siny) (cosx cosy + sinx siny) in the form of 1/2(sin2x + sin2y)?
1 answer
asked by
Anonymous
657 views
Simplify #3:
[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
1 answer
asked by
Anonymous
1,076 views
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
0 answers
asked by
Dave
1,454 views
Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus-
5 answers
asked by
MS
1,004 views
sinx+ siny/ (cosx+cosy)= tan 1/2 (x+y)
prove this identity
0 answers
asked by
JK
1,267 views
Prove the following identity:
1/tanx + tanx = 1/sinxcosx I can't seem to prove it. This is my work, I must've made a mistake
1 answer
asked by
Heather
791 views
Proving identity
(sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx/cosx))x 1/(cosx+1)
1 answer
asked by
sh
627 views
Verify the identity:
tanx(cos2x) = sin2x - tanx Left Side = (sinx/cosx)(2cos^2 x -1) =sinx(2cos^2 x - 1)/cosx Right Side = 2sinx
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asked by
Ashley
1,249 views
1/tanx-secx+ 1/tanx+secx=-2tanx
so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
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asked by
olivia
1,344 views