2sinx-cosx=3/sqrt. of 2

The equation 2sinx+sqrt(3)cotx=sinx is partially solved below.2sinx+sqrt(3)cotx=sinx sinx(2sinx+sqrt(3)cotx)=sinx(sinx)
1. 7 answers
2. asked by girly girl
3. 5,652 views
hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
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2. asked by elle
3. 752 views
For f(x) = 2sinx + (sinx)^3 + tanx find f'(pi/3). Ok, so what I tried was...f'(x) = 2cosx + cosx(3(sinx)^2) + (sinx/cosx) pi/3 =
1. 1 answer
2. asked by Mel
3. 692 views
Solve for x in the interval 0<=x<360:1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
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2. asked by `
3. 684 views
2sinx-cosx=3/sqrt. of 2
1. 1 answer
2. asked by cassy
3. 644 views
For the following question, we need to find the length of the polar curve:r= 2/(1-cosx) from pi/2 </= x </= pi dr/dx=
1. 1 answer
2. asked by Jenna
3. 735 views
Given that f(x) = 2sinx - cosx- Write f(x) in the form Asin(x+a) - Find the maximum value of 2sinx - cosx - Find the lowest
1. 4 answers
2. asked by sqleung
3. 804 views
sin2x+cosx=0 , [-180,180)= 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in
1. 1 answer
2. asked by Anonymous
3. 951 views
verify for sqrt(1-cosx)= sin/sqrt(1+cosx).I multiplied the right side by sqrt(1-cosx) and got sqrt(1-cosx)= sin*sqrt(1-cosx),
1. 3 answers
2. asked by unknown
3. 1,149 views
Which of the following are trigonometric identities?(Can be more then one answer) tanx cosx cscx = 1 secx-cosx/secs=sin^2x
1. 1 answer
2. asked by Jill
3. 4,833 views