2sin5xcos4x-sinx=sin9x Can u do this

2sin5xcos4x-sinx=sin9xCan u do this without triple angle formula and how
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2. asked by anon
3. 488 views
Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
1. 3 answers
2. asked by Anonymous
3. 949 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
1. 3 answers
2. asked by Anonymous
3. 787 views
Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
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2. asked by Tara
3. 1,060 views
Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
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2. asked by Maggie
3. 856 views
I need help solving for all solutions for this problem:cos 2x+ sin x= 0 I substituted cos 2x for cos^2x-sin^2x So it became
1. 1 answer
2. asked by Martha
3. 641 views
tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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2. asked by shan
3. 991 views
the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
1. 3 answers
2. asked by alex
3. 873 views
I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try.17. Sinx-1/sinx+1
1. 5 answers
2. asked by Kim
3. 1,151 views
If y=Sinx^Sinx^Sinx.......infinity then prove that dy/dx=2ycotx/1-ylog(sinx).?
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2. asked by Parikshit
3. 1,446 views