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2sin2x = cos2x for -

  1. 2sin2x = cos2x for - pi x pi
    1. answers icon 1 answer
    2. views icon 91 views
  2. Solve for x in the equation 2sin²x-1=cos²x+sinx
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    2. views icon 68 views
  3. Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
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    2. Brian asked by Brian
    3. views icon 837 views
  4. sin2x − cos2x − tan2x = 2sin2x − 2sin4x − 1/1 − sin2x for x = 45
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    2. thomas asked by thomas
    3. views icon 597 views
  5. Solve for x in the interval 0<=x<360:1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
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    2. ` asked by `
    3. views icon 697 views
  6. how does this work?(Sin2x+cos2x+2sin²x)/(sinx+cosx) = (sinx+cosx
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    2. Tim asked by Tim
    3. views icon 611 views
  7. Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
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    2. sh asked by sh
    3. views icon 790 views
  8. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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    2. Maria asked by Maria
    3. views icon 1,671 views
  9. Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π).8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve
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    2. Anonymous asked by Anonymous
    3. views icon 883 views
  10. find all solutions of the equation 2sin x cos2x-cos2x=0 over the interval 0<x<=pi
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    2. owo asked by owo
    3. views icon 2,247 views