2sec^2x -3tanx =5 for [0,2pi)

  1. 2sec^2x -3tanx =5 for [0,2pi)
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    2. tom asked by tom
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  2. 2sec^2x - 3tanx - 5 = 0over the interval 0 to 2pi x= 1.14, 4.28, 5.68, and 2.54 right?
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    2. tom asked by tom
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  3. 2sec^2x -3tanx =5 for [0,2pi)Please solve for the values of x for me.
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    2. tom asked by tom
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  4. 2sec^2x - 3tanx - 5 = 0I got x= 1.24 radians x= 4.38 radians x= -0.74 radians x= -3.88 radians
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    2. SkiMasktheSlumpGod asked by SkiMasktheSlumpGod
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  5. Could someone please help with this question.State the properties of y = 2sec(-2x + 180°) + 3. My answer: First I graphed y =
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    2. Matt asked by Matt
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  6. Prove that the following Trigonometric Identity is valid:1/(sin⁡(y)-1)-1/(sin⁡(y)+1)=-2sec^2 (y) Please any help or clues on
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    2. kat asked by kat
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  7. Am I right on this?2sec^2(2x)-8=0 2sec^2(2x)=8 divide by 2 sec^2(2x)=4 find square root sec(2x)=2 Now, would this simply be
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    2. Alex asked by Alex
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  8. if f(x)=3tanx +2
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    2. pete asked by pete
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  9. Differentiate x-3+3tanx
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    2. Sandra asked by Sandra
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  10. tan3x=(3tanx-tan^3x)/(1-3tan^2x)
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    2. Mayna asked by Mayna
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