2cosx=√2+√2+2cos4x

  1. 2cosx=√2+√2+2cos4x
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    2. neha asked by neha
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  2. For the following equation, why cannot I not solve it? I keep getting an error.-- 2cosx - 3 = 0 -- I first isolated for "x"
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    2. Anonymous asked by Anonymous
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  3. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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    2. shan asked by shan
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  4. Find the limit of(2cosx+3cosx-2)/(2cosx-1)as x tends to pi/3.
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    2. Alex asked by Alex
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  5. Find the volume of the solid obtained by rotating the region in the first quadrant enclosed by the curves y= tanx and y=2cosx
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    2. tom asked by tom
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  6. Determine the concavity and find the points of inflection.y=2cosx + sin2x 0≤x≤2pi y'=-2sinx + 2cos2x y"=-2cosx-4sinx How do
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    2. sh asked by sh
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  7. h t t p : / / w w w . j i s k h a . c o m / d i s p l a y . c g i ? i d = 1 2 6 7 4 1 7 1 8 8I don't follow your work Reiny
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    2. Kate RESPONSE asked by Kate RESPONSE
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  8. prove that(2cosx+1)(2cosx-1)= 1 +2cos2x
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    2. adil asked by adil
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  9. Having trouble verifying this identity...cscxtanx + secx= 2cosx This is what I've been trying (1/sinx)(sinx/cosx) + secx = 2cosx
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    2. Alex asked by Alex
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  10. Solve for [0,2pi)2cos4x + sqrt3 = 0
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    2. Anonymous asked by Anonymous
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