2cos^2x-3sinx=0

  1. Solve each equation for 0 is less than and equal to "x" is less than and equal to 3603sinx = 2cos^{2}x ----- I don't know how to
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    2. Anonymous asked by Anonymous
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  2. 2cos^2x-3sinx=0
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    2. LiNnda asked by LiNnda
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  3. How do you solve?3-3sinx-2cos^2(x) = 0
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    2. Sophie asked by Sophie
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  4. find the exact solutions2cos^2x+3sinx=0 the way it stands, that is a "nasty" question. Are you sure the second term isn't
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    2. Devon asked by Devon
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  5. how can i find all the exact solutions to the equation : 2cos^2x + 3sinx = 3the solutions have to be between [0,2pi)
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    2. Joe asked by Joe
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  6. Complete the table of values that can be used to graph f(x) = 7/3sinxx: 0, pi/2, pi 3pi/2, 2pi f(x) = 7/3sinx:
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  7. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  8. 1. Find y'(x) whenxsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - 3sinx) b) (3cosx - sec x) / (xsecytany - 3sinx) c)
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    2. Donna asked by Donna
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  9. Solve the equation on the interval [0,2pi).2sin^2x-3sinx+1=0 (2sinx+1)(sinx+1) I don't think I did the factoring correctly. When
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    2. Jan asked by Jan
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  10. I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!((3^3)^(cosx+2/3sinx))^2cosx+3
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    2. Anonymous asked by Anonymous
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