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2cos^2x-3sinx=0
Solve each equation for 0 is less than and equal to "x" is less than and equal to 360
3sinx = 2cos^{2}x ----- I don't know how to
8 answers
asked by
Anonymous
1,160 views
2cos^2x-3sinx=0
2 answers
asked by
LiNnda
1,218 views
How do you solve?
3-3sinx-2cos^2(x) = 0
6 answers
asked by
Sophie
725 views
find the exact solutions
2cos^2x+3sinx=0 the way it stands, that is a "nasty" question. Are you sure the second term isn't
0 answers
asked by
Devon
617 views
how can i find all the exact solutions to the equation : 2cos^2x + 3sinx = 3
the solutions have to be between [0,2pi)
1 answer
asked by
Joe
866 views
Complete the table of values that can be used to graph f(x) = 7/3sinx
x: 0, pi/2, pi 3pi/2, 2pi f(x) = 7/3sinx:
1 answer
19 views
cosA= 5/9 find cos1/2A
are you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
0 answers
asked by
Anonymous
828 views
1. Find y'(x) when
xsecy - 3y sinx = 1 a) (3ycosx - sec y) / (xsec^2y - 3sinx) b) (3cosx - sec x) / (xsecytany - 3sinx) c)
1 answer
asked by
Donna
802 views
Solve the equation on the interval [0,2pi).
2sin^2x-3sinx+1=0 (2sinx+1)(sinx+1) I don't think I did the factoring correctly. When
2 answers
asked by
Jan
2,596 views
I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!
((3^3)^(cosx+2/3sinx))^2cosx+3
1 answer
asked by
Anonymous
565 views