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2cos^2(x) = 13sinx - 5

  1. 2cos^2(x) = 13sinx - 5How do i solve for x? I think i have to use the sin^2x + cos^2x = 1, but I'm not sure how to use that. I
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    2. Savannah asked by Savannah
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  2. cosA= 5/9 find cos1/2Aare you familiar with the half-angle formulas? the one I would use here is cos A = 2cos^2 (1/2)A - 1 5/9 +
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    2. Anonymous asked by Anonymous
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  3. What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
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  4. how does 2cos(2x)-2cos(x)sin(x) becomes 2cos(2x)-sin(2x)? Try to explain each step simply.
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  5. Determine the solution of the equetion: 2cos x-1=0? 2cos x=0? and 2cos x+1=0?
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    2. Miley asked by Miley
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  6. solve 12cos^2X=8+13sinX between the window of -360 ¡Ü x ¡Ü 360
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    2. kelly asked by kelly
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  7. If 13sinx+5=0 and x�[0;270],determine witout the use of a calculator,the value of sin2x
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    2. Zinhle asked by Zinhle
    3. views icon 450 views
  8. Identify the equation for the following graph: (1 point) Responses y=2cos(2x) y is equal to 2 cosine 2 x y=−2cos(2x) y is
    1. answers icon 1 answer
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  9. Multiply then use fundamental identities to simplify the expression below and determine which of the following is not equivalent
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    2. Tristian asked by Tristian
    3. views icon 1,674 views
  10. Which cosine function has maximum of 2, a minimum of -2, and a period of 2pi/3?Choose from answers below, correct one please. y
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    2. views icon 47 views