2HCr4- + 3HS03- + 5H+

  1. 2HCr4- + 3HS03- + 5H+ -> 2Cr3+ + 3SO4^2- + 5H20.At t=0, 0.0249 mols of HCr04- are loaded in to 250ml of solution. After 1/10 of
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    2. Tri asked by Tri
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  2. When I invert the concentration of say this equation:2HCr4- + 3HS03- + 5H+ -> 2Cr3+ + 3SO4^2- + 5H20. and get RSRRE wrt HS03-,
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    2. Tri asked by Tri
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