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2C8H18(g)+25O2(g)-->16CO2(g)+18H2O(g) 0.290mol of octane is

2C8H18(g)+25O2(g)-->16CO2(g)+18H2O(g)0.290mol of octane is allowed to react with 0.600mol of oxygen.The limiting reactant is
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2. asked by Rose
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2C8H18(g)+25O2(g)+16CO2(g)+18H2O(g)0.290mol of octane is allowed to react with 0.600mol of oxygen.The limiting reactant is
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2. asked by Rose
3. 1,275 views
This balance equation shows the burning of octane in air. 2C8H18 + 25O2 ----> 16CO2 + 18H2O. How many grams of carbondioxide
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2. asked by Shane
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0. A common gasoline additive is octane, C8H18. When octane is burned it produces heataccording to the following equation.
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Calculate the standard enthalpy change for the reaction:2C8H18(l) + 17O2(g) --> 16CO(g) + 18H2O(l) Given: 2C8H18(l) + 25O2(g)
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2. asked by Anon
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HOW MANY GRAMS OF OCTANE WOULD BE NEEDED TO RELEASE 3,500 kJ OF HEAT?2C8H18 + 25O2-----> 16CO2 + 18H2O DeltaH= -5,530 kJ/mole of
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2. asked by Matthew
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What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal
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2. asked by Jeremiah latkuoth
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Calculate the standard enthalpy change for the reaction 2C8H18(l)+17O2(g)> 16CO(g) + 18H2O(l)Given
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2. asked by Nicole
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During the combustion of 5.00 g of octane, C8H18, 239.5 kcal (1002 kJ) is released.Balanced equation: 2C8H18+25O2→16CO2+18H2O
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2. asked by Timbs
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1=what is the percntage yeild of carbon dioxide if 4 moles of octane are burnt to produce 1350g of carbon dioxide2c8h18 + 25o2 =
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2. asked by sadia salem
3. 627 views