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25.5g C7H11NO7S (4-nitro-2-toluenesulfonoic acid dihydrate)

  1. 25.5g C7H11NO7S (4-nitro-2-toluenesulfonoic acid dihydrate) in 1.00*10^2g H2O (nonionizing solute)
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    2. Jose Reyes asked by Jose Reyes
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  2. Compute the boiling point of this Solution:25.5g C7H11NO7S (4-nitro-2-toluenesulfonoic acid dihydrate) in 1.00*10^2g H2O
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    2. Jose Reyes asked by Jose Reyes
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  3. Compute the freezing point of this Solution:25.5g C7H11NO7S (4-nitro-2-toluenesulfonoic acid dihydrate) in 1.00*10^2g H2O
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    2. Jose Reyes asked by Jose Reyes
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  4. Compute the freezing point of this solution: 25.5 g C7H11NO7S (4-nitro-2-toluenesulfoinoic acid dihydrate) in 100 g H2O.
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    2. Les asked by Les
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  5. WHAT IS THE FREEZING POINT OF THIS SOLUTION?25.5g C7,H11,N,O7,S(4-nitro-2-toluenesulfonic acid dihydrate) in 1.00x10^2g
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    2. Jose Reyes asked by Jose Reyes
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  6. WHAT IS THE BOILING POINT OF THIS SOLUTION?25.5g C7,H11,N,O7,S(4-nitro-2-toluenesulfonic acid dihydrate) in 1.00x10^2g
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    2. Jose Reyes asked by Jose Reyes
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  7. A buffer prepared by dissolving oxalic acid dihydrate (H2C2O4·2H2O) and disodium oxalate (Na2C2O4) in 1.00 L of water has a pH
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    2. Owen asked by Owen
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  8. factors affecting deviation of practical melting point from theoretical melting point of 3- nitro benzoic acid produced from
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  9. What mass of oxalic acid dihydrate , H2C2O4•2H2O, is required to prepare 220.0 ml of a 1.28 M solution of oxalic acid ?
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    2. Cynthia asked by Cynthia
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  10. What is the mole of oxalic acid?Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. *
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    2. Ivy asked by Ivy
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