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2(sinx)^2-5cosx-4=0

  1. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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    2. Anonymous asked by Anonymous
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  2. 2(sinx)^2-5cosx-4=0
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    2. Anonymous asked by Anonymous
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  3. x^3(sinx)/ 5cosx
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    2. jnky asked by jnky
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  4. y = x^3 sinx / 5cosx
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    2. jnky asked by jnky
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  5. 2(sinx)^2-5cosx-4=0Solve for all solutions between [0,2pi]
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    2. Anonymous asked by Anonymous
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  6. Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
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    2. Anonymous asked by Anonymous
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  7. Compute inverse functions to four significant digits.cos^2x=3-5cosx rewrite it as.. cos^2x + 5cosx -3=0 now you have a
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    2. Kate asked by Kate
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  8. Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
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    2. Tara asked by Tara
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  9. Compute inverse functions to four significant digits.cos^2x=3-5cosx cos^2x + 5cosx -3=0 now you have a quadratic, solve for cos
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    2. Kate asked by Kate
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  10. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
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    2. Maggie asked by Maggie
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