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10sinB+5 = sinB+5
10sinB+5 = sinB+5
1 answer
asked by
brittany
324 views
Given a = 31.5, b = 51.8, A = 33 degrees, find the value of c in triangle ABC.
bsinA = 51.8sin33 = 28.21 -> bsinA < a < b so
1 answer
asked by
K
1,105 views
Prove That Sin2A+ Sin2B +SIN2C/sinA+SINB+SINC=8sinA/sinB/2COSC/2
1 answer
asked by
Joel
1,002 views
If A+B+C=^(^=180) prove that
sinA + sinB - sinC = 4sinA/2 sinB/2 cosC/2
2 answers
asked by
ody
2,068 views
Solve the following questions
(1) SinB=Cos35 degrees (2) Cos286 degrees (3) SinB=Cos3B (4) Cos2B=Sin3B (5) Cos y= Sin(y+22
1 answer
asked by
Ande2
573 views
Use triangle ABC to write the value of sinB as a ratio.
Triangle A B C with right angle at A, and hypotenuse B C. The following
4 answers
asked by
GROOVE
2,245 views
SinA + sinB/sinA - sinB= tanA+B/2cotA-B/2
1 answer
asked by
sandy
1,124 views
If 3 sinb + 5 cosb =5 then show that 3 cosb - 5 sinb =±3
1 answer
asked by
Anonymous
284 views
A+B=90 then sina sinb=
1 answer
asked by
anya
661 views
If A+B=90° then what is the range of SinA•SinB
1 answer
asked by
meet
810 views