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1. Solve 3=log8+3logx 2. Solve

  1. 1. Solve 3=log8+3logx2. Solve 2logx-log4=0
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    2. Anonymous asked by Anonymous
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  2. Drop the logs solve for xlog8 x + log8 (x + 6) = log8 (5x + 12)
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  3. solve: log8(w-6)=2-log8(w+15)note: the 8 is to be little at the bottom right corner of log
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    2. Britt asked by Britt
    3. views icon 635 views
  4. solve: log8(w-6)=2-log8(w+15)note: the 8 is to be little at the bottom right corner of log
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    2. Britt asked by Britt
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  5. How do I start to solve -2log8(x+1) = -8?I think -2log8(x+1) is log8^(x+1)to the 2nd but then what do I do because then I think
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    2. Anna asked by Anna
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  6. Solve the equation : 8^2x-1 = 16^x+1i know you have to log both sides log8^2x-1 = log16^x+1 and then you use the exponential
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    2. Brooke asked by Brooke
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  7. Hi can someone solve this for me.2logy = log2 + 3logx, 2 ^ y = 4 ^ x
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    2. Micheal asked by Micheal
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  8. log8 2 +log8 4x^2 =2 solve
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  9. If e^(x+3logx) then prove that dy/dx=x^2(x+3)e^x....can anyone help me out...plz note 3+logx is in adition with x and is the
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    2. Abhishek asked by Abhishek
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  10. PLEASE CHECK MY ANSWERS1. Write f(x)=4^x-3 in f(x)=ab^x F(x)=(1/64)(4)^x 2.solve for x 4^x+2=3^x-5 X=-log4/3(3888) 3.solve for x
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    2. Lexy asked by Lexy
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