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1. 4sin^2x=3tan^2x-1 2. 8cos^2x-4cos^4x=3 3.
1. 4sin^2x=3tan^2x-1
2. 8cos^2x-4cos^4x=3 3. 3secx-cosx=2
2 answers
asked by
Michael
3,653 views
(3-4sin^2A)(1-3tan^2A) =(3-tan^2A)(4cos^A-3)
0 answers
asked by
Shreya
772 views
(3-4sin^2a)(1-3tan^2a)=(3-tan^2a)(4cos^2a-3)
1 answer
asked by
Optional
899 views
Prove that:(3-4sin^2A) (1-3tan^2A)=(3-tan^2A)(4cos^2A-3)
1 answer
asked by
Rishabh
1,467 views
(3-4sin^2thita)(1-3tan^A)=(3-tan^2A)(4cos^2A-3)
4 answers
asked by
Soniya
377 views
Prove that (3-4sin^2A) (1-3Tan^2A)= (3-tan^2A) (4cos^2A-3)
8 answers
asked by
Alina maharjan
12,142 views
If sec x = 17/8; verify that 3 - 4sin^2x /4cos^2x -3 = 3- tan^2x / 1-3tan^2x.. I have used x in place of theta. It isn't
1 answer
asked by
Agile
960 views
Solve the equation for solutions in the interval 0<=theta<2pi
Problem 1. 3cot^2-4csc=1 My attempt: 3(cos^2/sin^2)-4/sin=1
2 answers
asked by
Renee
1,718 views
Which equation would the table of values represent? 0, 3 pi over 2, 3 pi, 9 pi over 2, 6 pi. 0, 4, 0, -4, 0 (1 point) Responses
1 answer
90 views
Prove:
cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) =
38 answers
asked by
Anonymous
2,748 views