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1. (-8cosxsinx+4cos2x)^2 +(4cosx^2+8sinxcosx)^2 2. cos(α-β)cosβ-sin(α-β)sinβ
1. (-8cosxsinx+4cos2x)^2 +(4cosx^2+8sinxcosx)^2
2. cos(α-β)cosβ-sin(α-β)sinβ 3. 1+(sinx-cosx)(sinx+cosx) 4.
2 answers
asked by
Anna
672 views
Simplify:
1. sin(α+β)+sin(α-β) 2. (-8cosxsinx+4cos2x)^2 + (4cos^2x+8sinxcosx)^2 3. sqrt(sin^4xcosx) * sqrt(cos^3x)
2 answers
asked by
Anna
1,094 views
1. (2cosx-2secx)(3cosx^2+3secx^2+β)
2. (16tanxsecx-4secx)/(8tanxsecx+4secx) 3.sinxcosx^3+cosx^4 (hint: GCF) 4. (cosβ+sinβ)^2
3 answers
asked by
Anna
637 views
Determine the general solution of 8 cos^2x - 4cosx - 1 =0
(8cos^2x - 4cosx)/8 =1/8 cos^2x - 4cosx=1/8 cos^2x/cosx =1+4cosx/cosx
1 answer
asked by
Bontle
722 views
Let f(x)=9sinx/2sinx+4cosx.
Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent
0 answers
asked by
Leslie
946 views
Complete the table of values that can be used to graph f(x)=−4cosx .(2 points) x f(x)=−4cosx 0 π2 π 3π2 2π
1 answer
94 views
Complete the table of values that can be used to graph f(x)=−4cosx
.(2 points) x f(x)=−4cosx 0 π2 π 3π2 2π
1 answer
105 views
a. Draw the graphs of y=4cosx and y=2x-x on the same set of axes for -2π<=x<=2π
(done) b. Explain why all these solutions of
1 answer
asked by
anon
473 views
8sinxcosx=1
I don't know where to go after 2sinxcosx=1/4
2 answers
asked by
Lily
1,912 views
Write the equation of the periodic function based on the graph.
(1 point) Responses y=−4cosx y equals negative 4 cosine x
1 answer
101 views