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1×sinx^2-cos^2x
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
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Anonymous
917 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm
(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
3 answers
asked by
Anonymous
756 views
Simplify sin x cos^2x-sinx
Here's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1 answer
asked by
Tara
1,034 views
Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
1 answer
asked by
Maggie
816 views
I need help solving for all solutions for this problem:
cos 2x+ sin x= 0 I substituted cos 2x for cos^2x-sin^2x So it became
1 answer
asked by
Martha
617 views
tanx+secx=2cosx
(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
0 answers
asked by
shan
958 views
the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
3 answers
asked by
alex
837 views
I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try.
17. Sinx-1/sinx+1
5 answers
asked by
Kim
1,125 views
If y=Sinx^Sinx^Sinx.......infinity then prove that dy/dx=2ycotx/1-ylog(sinx).?
1 answer
asked by
Parikshit
1,427 views
Verify the Identity:
sin(x+π)/cos(x+3π/2) =tan^2x-sec^2x I've done: sinxcosπ+cosxsinπ / cosxcos(3π/2) - sinxsin(3π/2)
2 answers
asked by
Phil-- HELP NEEDED ASAP
848 views