1×sinx^2-cos^2x

  1. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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    2. Anonymous asked by Anonymous
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  2. Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
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    2. Anonymous asked by Anonymous
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  3. Simplify sin x cos^2x-sinxHere's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
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    2. Tara asked by Tara
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  4. Hello! Can someone please check and see if I did this right? Thanks! :)Directions: Find the exact solutions of the equation in
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    2. Maggie asked by Maggie
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  5. I need help solving for all solutions for this problem:cos 2x+ sin x= 0 I substituted cos 2x for cos^2x-sin^2x So it became
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    2. Martha asked by Martha
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  6. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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    2. shan asked by shan
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  7. the problem is2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
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    2. alex asked by alex
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  8. I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try.17. Sinx-1/sinx+1
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    2. Kim asked by Kim
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  9. If y=Sinx^Sinx^Sinx.......infinity then prove that dy/dx=2ycotx/1-ylog(sinx).?
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    2. Parikshit asked by Parikshit
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  10. Verify the Identity:sin(x+π)/cos(x+3π/2) =tan^2x-sec^2x I've done: sinxcosπ+cosxsinπ / cosxcos(3π/2) - sinxsin(3π/2)
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    2. Phil-- HELP NEEDED ASAP asked by Phil-- HELP NEEDED ASAP
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