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1) (sin2t) (cos5t) + (cos2t)
1) (sin2t) (cos5t) + (cos2t) (sin5t)
2) {1/(sec x - 1)} - {1/(sec x +1)} = 2 cot^2 x
1 answer
asked by
Britt
582 views
Use identities to simplify each expression.
1) (sin2t) (cos5t) + (cos2t) (sin5t) 2) {1/(sec x - 1)} - {1/(sec x +1)} = 2 cot^2 x
1 answer
asked by
Britt
632 views
If f is a vector-valued function defined by <sin2t, cos2t> then what is f '' (pi/4)?
I think it is <-4, -√2/2>.
2 answers
asked by
Anonymous
930 views
find the tangent line equation at x=cost+sin2t, y=sint+cos2t, t=0
3 answers
asked by
Lielle
1,017 views
1) show that: 1-cos2t divided by sin2t= TANt
2) show that: 1-(cos2t divided by (cos x cos)t)= (TAN x TAN)t
1 answer
asked by
Craig
566 views
find the solutions of the equation that are in the interval [0,2pi)
(a) sin2t+sint=0 (b)cost-sin2t=0
0 answers
asked by
Hayli
499 views
find the solutions of the equation that are in the interval [0,2pi)
(a) sin2t+sint=0 (b)cost-sin2t=0
1 answer
asked by
Hayli
625 views
need help simplifying some trig identities such as:
(csc t) (sin t) cos t = 0.75 and tan t = 0.88, find sec t and cot t; (cot2t)
1 answer
asked by
angelia
847 views
integrate 10*e^5t*cos5t.
1 answer
asked by
Abhi
477 views
find the dy/dx of s(t)= (4/3pi)sin3t+(4/5pi)cos5t
1 answer
asked by
Millie
2,829 views